(4x^3+4x^2-7x+2)/(x-2)

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Solution for (4x^3+4x^2-7x+2)/(x-2) equation:


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

(4*x^3+4*x^2-(7*x)+2)/(x-2) = 0

(4*x^3+4*x^2-7*x+2)/(x-2) = 0

4*x^3+4*x^2-7*x+2 = 0

4*x^3+4*x^2-7*x+2 = 0

{ 1, -1, 2, -2 }

1

x = 1

4*x^3+4*x^2-7*x+2 = 3

1

-1

x = -1

4*x^3+4*x^2-7*x+2 = 9

-1

2

x = 2

4*x^3+4*x^2-7*x+2 = 36

2

-2

x = -2

4*x^3+4*x^2-7*x+2 = 0

-2

x+2

4*x^2-4*x+1

4*x^3+4*x^2-7*x+2

x+2

-4*x^3-8*x^2

2-4*x^2-7*x

4*x^2+8*x

x+2

-x-2

0

4*x^2-4*x+1 = 0

DELTA = (-4)^2-(1*4*4)

DELTA = 0

x = 4/(2*4)

x = 1/2 or x = 1/2

x in { 1/2, 1/2, -2}

(x-1/2)^2*(x+2) = 0

((x-1/2)^2*(x+2))/(x-2) = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x-1/2 )

x-1/2 = 0 // + 1/2

x = 1/2

x in { -2, 1/2, 1/2 }

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